00:01
And we're looking at chapter 5, section 1, problem number 44.
00:06
We're given a function y equals natural log of x squared plus 1 minus x to the 0 .3.
00:14
And we are asked to find the intervals of where this function is increasing and decreasing using a graphing calculator.
00:22
So since we're trying to find increasing decreasing, which would be when the derivative is less than 0 or greater than 0, we can start by going ahead and finding our derivative.
00:34
So i'm going to say y prime equals.
00:36
We know that the derivative of natural log of u is 1 over u.
00:41
So 1 over x squared plus 1 times the derivative of you.
00:48
So times derivative of x squared plus 1, which would be times 2x.
00:55
I'll put it in parentheses, so it doesn't look like a decimal.
00:58
And then here we have a power rule, so minus 0 .3, we move the exponent to the front, and then subtract by 1, so to the negative 0 .7.
01:11
Or cleaning it up just a little.
01:14
All right, 2x over x squared plus 1, minus 0 .3x to the negative 0 .7.
01:36
Okay, and so if this is y -prime, then what i'm going to do is punch that into the calculator...