For each of the following linear systems find a permuted $L U$ factorization of the coefficient matrix and then use it to solve the system by Forward and Back Substitution.
$$
\begin{aligned}
4 x_1-4 x_2+2 x_3 & =1, \\
-3 x_1+3 x_2+x_3 & =3, \\
-3 x_1+x_2-2 x_3 & =-5
\end{aligned}
$$
(a) $-3 x_1+3 x_2+x_3=3$,
$$
y-z+w=0,
$$
$$
y+z=1,
$$
(b)
$$
\begin{aligned}
& x-y+z-3 w=2, \\
& x+2 y-z+w=4 .
\end{aligned}
$$
$$
\begin{aligned}
x-y+2 z+w & =0, \\
-x+y-3 z & =1,
\end{aligned}
$$
(c)
$$
\begin{aligned}
x-y+4 z-3 w & =2, \\
x+2 y-z+w & =4 .
\end{aligned}
$$
0\end{array}\right)$.
Do you always obtain the same result? Explain why or why not.
1.4.24. (a) Find three different permuted $L U$ factorizations of the matrix $A=\left(\begin{array}{rrr}0 & 1 & 2 \\ 1 & 0 & -1 \\ 1 & 1 & 3\end{array}\right)$. (b) How many different permuted $L U$ factorizations does $A$ have?