00:01
In this question, we are using thesper to determine the bond angle in the following molecules.
00:08
So in part a, we are looking at cl2o.
00:12
We're going to determine how many electrons we are working with so we can draw our structure.
00:17
We have two chlorines, each with seven electrons, and we have an oxygen with six electrons.
00:22
That's 20 electrons to work with.
00:24
So we have chlorine, oxygen, and chlorine.
00:29
We have two bonds here, and each.
00:31
Each of our bonds contains two electrons.
00:35
So that means we have four electrons that have been accounted for and 16 remaining.
00:40
We distribute these on our chlorines first, so that's 6, 12.
00:46
We have four electrons remaining and those four will go on our central atom of oxygen.
00:54
So here we have four areas in which electrons exist, which means we are in the overall vespers arrangement of tetrahedral.
01:02
And these have bond angles of 109 .5 degrees.
01:07
Since we are dealing with two lone pairs, there will be some electron repulsion, making the bond angle slightly less than 109 .5 degrees.
01:16
In part b, we are looking at ccl4.
01:21
In this, we have a carbon with four valence electrons, and four chlorines, each with seven valence electrons.
01:26
That adds to 32.
01:28
Carbon is in the center with four chlorines surrounding, it.
01:34
We have four bonds each with two electrons, meaning eight electrons have been accounted for, and we have 24 remaining.
01:40
We fill our outer elements or outer atoms, so that's 6, 12, 18, and 24.
01:52
All our electrons have been accounted for.
01:55
We have four bonding domains, meaning we are in tetrahedral with 109 .5 degree bond angle...