00:01
In this problem, we're asked to calculate the grams of product, the one that's indicated.
00:26
When 25, i think i'm on the wrong one here.
00:35
Let me go back up here.
00:40
Uh -oh, my pen's going to die.
00:42
Okay, this is lithium.
00:48
When 15 grams, when my pen dies, i'm going to have to switch of my first reactant and 10 .0 grams of my second.
01:09
Reactant are used.
01:18
My first product reaction is 4lis plus o2g yields 2li2o.
01:34
And this is the product we're looking at.
01:39
I'm going to go way down so i can get these written, and then i'll come back and bring them out.
01:45
For my second, i have f .e .203 plus 3 ,8.
01:53
And that is 2fe plus 3h2ol and we're looking at iron.
02:10
Finally for c we're looking at aluminum sulfide reacting with 6h2ol.
02:24
And my products are two aluminum hydroxides plus 3h2s.
02:43
And my product will be the one i'm looking at is h2s so i've underlined my products.
02:50
Let's begin.
02:53
Okay, i almost picked the wrong one there.
02:57
So let's start with our aluminum, first reactant and second reactant.
03:03
Got it.
03:06
So i'm going to have 15 .0 grams of lithium and 10 .0 grams of oxygen.
03:21
For each of these, we're going to go to mass of product.
03:28
Lithium is 6 .94 grams per mole, and i have a 2 to 4 mole ratio for lithium and lithium oxide.
03:48
My mass of lithium oxide is 29 .88 grams per mole.
04:01
This equals 18.
04:08
This equals, i haven't done my math yet on that one.
04:12
Let's get ready for this.
04:13
32 .00 grams of 02 per mole of 02.
04:21
I have a 1 to 2 mole ratio and this is still 29 .88 grams per mole.
04:43
Let me get my calculator.
04:45
15 times 2 times 29 .88 divided by 6 .94 divided by 4.
04:55
This equals 32 .3.
05:00
Of la20 through la20.
05:03
Next i have 10 times 2 times 29 .88 and here i get 18 .7 grams of lithium two oxide.
05:17
This would be the correct value...