00:06
For 34a, we have m equal to ai, giving us 1 .02, 036, 26, 7, in our identity matrix.
00:25
Now we're going to have row 3 minus 2 of row 1 to 0 out row 1.
00:30
Then we're going to have column 3 minus 2, column 1.
00:38
So that's going to produce 1 -0 -0 -0 0 -0.
00:46
We have 3 and 6 here.
00:48
R row 3 minus 2 row 1.
00:51
We have 6 minus 0, and we hit 7 minus 4, which is 3.
01:04
Then we have 1 -1, but this negative 2 from earlier is there now.
01:14
And next we're going to have the following row 3 minus 2 row 2 and we're going to have column 3 minus 2 column 2 so now we'll have 1 0 0 0 0 0 0 0 and this will be 1 0 0 0 0 0 0 0 0 and 1.
02:04
So now we have our diagonal and we have p transpose.
02:11
So we can write this as p equals, remember this is d, and this is p transpose, is 1, 0, 0 ,0, 0, 0, 0, 0, 0, 0, 0, and 0, 1.
02:27
And d is going to equal our diagonal of 1, 3, and negative 9.
02:38
Now for b, m equals ai again, so we have 1, negative 2, 1 ,000, 1 ,000.
02:54
015 and 05 negative 3 multiplied by the identity matrix.
03:06
And so we're going to have 2 row 1.
03:09
Oh, i'm sorry.
03:11
I miswrote this.
03:24
It's going to be negative 2, 5, 3, 1, 3, 13, negative 2.
03:30
Two, we're going to have two row one plus row two and row three minus row one to zero at that column.
03:42
We're also going to do two column one plus column two and column three minus column one.
03:58
So if we look at row one and row two, that's going to change this to 015.
04:09
Then our third row is going to change to 0 .5, negative 3...