for-each-of-the-questions-46-50-two-of-the-suggested-answers-will-be-correct-select-the-two-answers-

Question

For each of the questions 46-50, two of the suggested answers will be
correct. Select the two answers that are best in each case, and then fill in both of
the corresponding circles on the answer sheet.
Which of the two velocity vs. time graphs depict situations of uniform
accelerated motion? Select two answers.
a. IMAGE IS NOT AVAILABLE TO COPY
b. IMAGE IS NOT AVAILABLE TO COPY
c. IMAGE IS NOT AVAILABLE TO COPY
d. IMAGE IS NOT AVAILABLE TO COPY

Vishal Gupta · Accepted Answer

high. In the given problem, we have to identify the we T. Kirk representing uniformly accelerated motion and we know a uniformly accelerated motion is represented by straight nine velocity time curves, as we know, acceleration is given by that&#x27;s slow of we D. Good. So when the car is in the form of a straight line means the slope will remain constant, means the acceleration will remain constant. So here the curves represented in figure B, which is a straight line parallel to the X axis, or we can say time axis and occur represented in figure B. Like this, these two curves are here representing uniformly excellent in motion. So we can say here our options B and be art correct. Thank you.

Ze-Han Lee · Answer

So in this problem, we need to find out which two has, uh, is the pig is depicting the uniform accelerating system. So we have basically Ah. So this one and this one All right, Bt so this to characterize the uniform a sensory system. So although this one x generation zero and well, this works generation is ah ah is negative, it&#x27;s negative. All right. But for the other two, like this one and this one TV, as you can see no to the change of the change of the velocity is no union for right. So a here is not yearning for him. And a here is also no uniforms, okay?

Ze-Han Lee · Answer

All right, So in this problem, we have a depiction like this, and we have full statements. The 1st 1 says that inmate depicted, Ah, vertical displacement, but this time as object of force within the with no air resistance. So this is a correct. Okay, it&#x27;s just a parabola and ah ah, the bees. Is that the kind of energy business time as the object of falls with snow air resistance that this is incorrect. So for this situation, that kind of energy will increase will keep increasing. So it is not right. And the c c. Is that the kind of energy business time as that? Well, Kate files. Ah, flies at a constant speed, but stepped labors few. So this is incorrect. So in that sense, the velocity will be a constant. Uh, yes. And because the velocities constants that kind of energy, the kinetic energy is constant undies. Is that a potential energy? But this time as an object of fools with no air resistance. So this is a correct Okay,

Ze-Han Lee · Answer

So in this problem, a car is Ah, big center Radium with constant velocity. Eight. Okay, so, uh, it is so supposed initially the velocity of the car is V and the Stop it stop as a distance off D. So we&#x27;ll have relation. Be squid over to a equal d right. And we can also find out Ah, the time for ah, for the, uh for this. Ah, the whole process. Because we have eight times t it cov right so I can see that t equal vt by a So if we double the velocity, so let&#x27;s see that. Firstly, let&#x27;s see the change of the d r. A so it would double the velocity. We&#x27;ll have ah, stop at business. That&#x27;s city prime. Okay, So deep prime equal to Reese. Quit developing. A. It is only about two A. That&#x27;s because the acceleration were not changed. Okay, so this gives you Ah, actually, this gives you two full times deep, all right? And the total time has expression eight times t prime equal to be so. We have turned out to t equal to V over a or that equal two times teak. So there&#x27;s a T prime to Dempsey. So we can see from this to, ah, conclusions that the distances quotable and the total time is just doubled, okay?

Kristela Garcia · Answer

in this problem, we need to choose two answers that allow my object to be in translational equilibrium. Now translation equilibrium means that my object is not speeding up or slowing down translational e. Now this means Lee nearly is another word to think of it. So in order for that to happen, I need the sum of my forces to be equal to zero, which tells us that the sum of my forces being eight, what zero makes my acceleration also equal to zero. So be it and see the 1st 1 part a tells us kinetic energy has to be equal to zero. That&#x27;s not true because it could be moving at a constant speed which would still give us a net force of zero and an acceleration of zero, and that would still be in linear or equilibrium. Translational equilibrium. The network doesn&#x27;t need to be zero because that would be rotational equilibrium, so rotational equilibrium would require a net torque of zero. But again, it wasn&#x27;t talking about rotational equilibrium, so d is out

Keshav Singh · Answer

for this problem on the topic of kinda Matics in one dimension we are showing the position of first time graph for two bicycles A and B. And we want to answer various questions about their motion. Firstly, we want to identify any instant at which the two bicycles have the same velocity. Now the two bicycles will have the same velocity at any time where the instantaneous slopes of the ex besties graphs are the same since the slope of the position was time graph gives the velocity And that occurs near the time T1 is marked on the graph next for part B. We want to know which bicycle has the larger acceleration bicycle A has the larger acceleration because its graph is concave upward, indicating a positive acceleration bicycle. B, however, has no acceleration since its graph has a constant slope for part C. We want to know the instance at which the bicycles are passing each other and they will pass each other at the times when the two graphs cross, because they both have the same position at that time. The ground for the steepest slope is the faster bicycle, so it is the one that is passing at that instant. So the first, at the first crossing bicycle B. Is passing bicycle A. And at the second crossing bicycle A. Is passing bicycle B. Next we want to know which bicycle has the larger instantaneous velocity. Now, bicycle B has the highest instantaneous velocity at all times until time. T. One where both graphs have the same slope For all times after T. one bicycle a has the highest entertaining its velocity. So the largest instantaneous philosophy is for bicycle A. At the latest time shown on the graph. And, lastly, for part E, you want to know which bicycle has the larger average velocity. The bicycles appear to have the same average velocity. If the starting point of the graph for a particular bicycle is connected to the ending point with a straight line. The slope of that line is the average velocity, and both appear to have the same slope for that average line.

Problem

For each of the questions 46-50, two of the sugge…

Problem 46 Easy Difficulty

Answer

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