This means we need to find $f(f^{-1}(x))$.
We are given $f^{-1}(x) = -3x + 6$. So, we need to find $f(-3x + 6)$.
We are given $f(x) = -\frac{1}{3}x + 2$. So, we can substitute $-3x + 6$ for $x$ in this expression:
$f(-3x + 6) = -\frac{1}{3}(-3x + 6) +
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