Question
For each pair of inverse functions, show that $\left(f \circ f^{-1}\right)(x)=x$ and $\left(f^{-1} \circ f\right)(x)=x$.$f(x)=\frac{3}{x^{\prime}} f^{-1}(x)=\frac{3}{x}$
Step 1
First, let's find the expression for $\left(f \circ f^{-1}\right)(x)$: $\left(f \circ f^{-1}\right)(x) = f\left(f^{-1}(x)\right) = f\left(\frac{3}{x}\right)$ Now, we plug in the expression for $f(x)$: $f\left(\frac{3}{x}\right) = Show more…
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