This means we need to find $f(f^{-1}(x))$.
We are given that $f^{-1}(x) = x^3 - 7$. So, we need to find $f(x^3 - 7)$.
We are given that $f(x) = \sqrt[3]{x+7}$. So, we can substitute $x^3 - 7$ for $x$ in the expression for $f(x)$:
$f(x^3 - 7) = \sqrt[3]{(x^3 -
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