Question
For each piecewise-defined function(a) calculate $f(-1), f(0), f(1),$ and $f(2),$ and (b) sketch a graph of $f$.$f(x)=\left\{\begin{aligned} 4 x-1, & \text { if } x<0 \\ 2, & \text { if } x=0 \\-3 x+5, & \text { if } x>0 \end{aligned}\right.$
Step 1
For $f(-1)$, since -1 is less than 0, we use the first part of the piecewise function, which is $4x - 1$. Substituting -1 for x, we get $4(-1) - 1 = -4 - 1 = -5$. Show more…
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For each piecewise-defined function, (a) calculate $f(-1), f(0), f(1)$, and $f(2)$, and (b) sketch a graph of $f$. $$ f(x)=\left\{\begin{aligned} 4 x-1, & \text { if } x<0 \\ 2, & \text { if } x=0 \\ -3 x+5, & \text { if } x>0 \end{aligned}\right. $$
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For each piecewise-defined function (a) calculate $f(-1), f(0), f(1),$ and $f(2),$ and (b) sketch a graph of $f$. $f(x)=\left\{\begin{aligned} 3 x+1, & \text { if } x \leq 0 \\ 4, & \text { if } 0<x \leq 1 \\ x^{3}, & \text { if } x>1 \end{aligned}\right.$
For each piecewise-defined function, (a) calculate $f(-1), f(0), f(1)$, and $f(2)$, and (b) sketch a graph of $f$. $$ f(x)=\left\{\begin{aligned} 3 x+1, & \text { if } x \leq 0 \\ 4, & \text { if } 0<x \leq 1 \\ x^{3}, & \text { if } x>1 \end{aligned}\right. $$
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