For nitrogen gas, $c_{v}=740 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}$. Assuming it to behave like an ideal gas, find its specific heat at constant pressure. (The molecular mass of nitrogen gas is $28.0 \mathrm{~kg} / \mathrm{kmol} .$ )
Method 1
$$c_{p}=c_{v}+\frac{R}{M}=\frac{740 \mathrm{~J}}{\mathrm{~kg} \cdot \mathrm{K}}+\frac{8314 \mathrm{~J} / \mathrm{kmol} \cdot \mathrm{K}}{28.0 \mathrm{~kg} / \mathrm{kmol}}=1.04 \mathrm{~kJ} / \mathrm{kg} \cdot \mathrm{K}$$
Method 2
Since $\mathrm{N}_{2}$ is a diatomic gas, and since $\gamma=c_{p} / c_{v}$ for such a gas,
$$
c_{p}=1.40 c_{v}=1.40(740 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K})=1.04 \mathrm{~kJ} / \mathrm{kg} \cdot \mathrm{K}
$$