00:01
So to start this problem off, we're going to do a free body diagram.
00:06
So we have our beam.
00:26
We have a force at b going in the y direction, as well as a in the y direction.
00:34
And this entire thing is l, and w is equal to...
00:51
So we take the moment at a, which is equal to b in the y direction times l, minus one half wl and 2l over 3.
01:09
2 thirds of the distance.
01:16
And solving for b in the y direction, we get wl over 3.
01:24
Then we can do the sum of forces in the y direction.
01:29
And we have a plus b minus 1 half wl and a ends up equal in to wl over 6.
01:51
So we can do a cross section between a, b of a certain distance, like we can call it x from a, and there'll be a sheer force and a moment.
02:05
So something like i just broke it here.
02:17
And we have sheer force and a moment.
02:24
So we can calculate by doing v and the integral wx.
02:34
Which is equal to this.
02:45
And solving for the integral, we get negative 1 half w x squared over l plus c1.
02:59
So that's our shear force.
03:00
And then moment, same thing pretty much.
03:03
We're just doing the integral now of the shear.
03:08
That's just equal to negative 1 .5 w x squared of l plus c1 d x.
03:18
And solving for that, we get negative negative one sixth, w x cubed over l plus c1x plus c2...