00:01
We're now asked to go back and look at problems 43 and 44 in which we had a beam with the distributed load on each end and then a point load in the middle.
00:14
That was some constant times the total distributed load acting on one of these sides.
00:29
So in the first case, we told that p was w times a, where this region here had a length a and the magnitude of the distributed load was w, which would have units of force per length.
00:49
In the second case, we were said that we were had a value of a point load of 3wa.
01:00
So if we look back at those problems here, let's see here.
01:07
We can see the one case we had had this kind of distribution.
01:12
And then the other case, we had this distribution.
01:18
So we can look at what we get for the, as we vary that constant.
01:29
So if we plot that as for a bunch of values of that constant, so p is now equal to k -wa.
01:38
So we bought that for a bunch of values of k.
01:40
So here we have zero and here we have three.
01:43
This were the kind of the extreme cases.
01:47
This is where we have one as what we had before.
01:52
And so each of these is one quarter of k.
01:56
So we can kind of get an idea of what's going on here.
01:59
Is that, you know, somewhat one, somewhere in this region here, a little bit over one, we will have where the minimum and the maximum are equal.
02:18
And what we can find is, what we see is that this minimum always occurs in region, in the central region, where there's just a point load acting.
02:31
So we really only need, we need to look at the function that describes the moment in that region...