00:01
Okay, so in this problem we're given two capacitors in series with one another like this.
00:08
And they have 150 and 120 nanofarad capacitances.
00:16
So 150 nanofarad and then 120 nanofarad.
00:23
And what else are we given? and then the total difference is 36 volts from a to b.
00:31
So here's a, here's b, v delta v is 120 volts.
00:41
And the question is, then, what's the total charge stored in the network? so to do that, let's find the equivalent capacitance.
00:53
So a, we want to get q, close question mark.
00:57
So c equivalent, if they're in series, it adds inverse.
01:01
So we're going to do 1 over 150 plus 1 over 120.
01:09
Both of those are nanofarads, but it's a little painstaking to write.
01:13
So i'm not going to write, at least small things.
01:17
So i'm going to plug that into a calculator to see what i get.
01:28
So that's 66 .7 nanofarads.
01:38
And then we can figure out the charts.
01:40
It's going to be put on the system because q is equal to cv.
01:45
C is q or v, so q is cv.
01:48
And so we just want to take this 66 .7 and multiply it by 120 volts to get 8 ,000 times 10 to the minus 9.
02:00
So let's see, times 10 to the minus 9, 8 times 10 to the minus 6.
02:08
So that's going to be 8 microculomes.
02:16
And for part b, we want to get the truce.
02:20
Charge on each capacitor.
02:22
So each capacitor is going to be, it's going to get this eight microculem because the charge will come out from the battery onto here.
02:32
And that's going to put eight microculems here, polarize this to be minus eight, polarized this little metal piece connecting the plates to make this plus eight.
02:43
And then this is going to be minus eight.
02:47
So we could, yeah, i can kind of imagine.
02:50
And so therefore it's going to be eight microculems on each because they're in parallel.
03:02
And c asks the total energy stored and the network.
03:12
So what we want to do is do, i think you can actually let's like test this.
03:20
So you could do the charge on the energy on each and add them.
03:25
You could also use the equivalent capacitance.
03:28
So i'm just going to test this idea out.
03:31
So let's do this simpler one first.
03:33
I think it's going to be you should use the equivalent capacitance and then the voltage.
03:40
So let's use u as one -half cv squared.
03:47
And then i'll use c equivalent.
03:51
So plugging that into a calculator, let's see.
03:55
I get, oh, so let's see, one half, 6 .7, 10 of the minus 9, and then b squared...