00:01
Hi there, so for this problem, we are given this circuit that is shown in here.
00:06
We are given the values for the resistance, the capacitance, and also for the end.
00:12
So for part a of this question, we are asked to determine the charges on the capacitors.
00:19
For part a, for the capacitor, c1.
00:24
So we need to determine its charge.
00:28
So with that said, first of all, we are going to find the total resistance in this circuit.
00:36
As you can see from the figure, the resistors are connected in parallel, so the equivalent resistance that we're going to call you simply as capital r is equal to 1 divided by the resistance 1 plus 1 divided by the resistance 2 and the inverse of all of this.
00:55
So we just simply substitute the value, so we will have 1.
00:58
Divided by two kilo -ooms plus one divided by three kilo -ooms.
01:06
Remember that kilo kilo means 10 to the 3 and we just elevate all of these to the minus 1.
01:13
So from this we obtain a value of 1 .20 kilo -ooms.
01:20
And the total capacitance, as you can see from the figure, since the capacitors are in parallel, the equivalent capacitance is just the sum of the capacitance 1 plus the capacitance 2, then this is equal to 2 microphorets plus 3 microurettes.
01:42
So from this, we obtain just simply 5 microferrets.
01:48
And then the maximum charge that we can obtain from this is equal to the equivalent capacitance times the nph.
01:57
So that will give us the value of 5.
02:00
Micro -farrates times the nf 120 bowls.
02:05
So from this we obtain 600 microlums.
02:10
And now we can also obtain the constant tau.
02:15
That will be the period between the resistance and the capacitance.
02:19
This will be 1 .2 times 10 to the 3 oms for the resistance.
02:25
And the capacitance that we obtain from this is 5 times 10 to the minus 6 ferrets.
02:31
So from this we obtain a value of 6 times 10 to the minus 3 seconds.
02:40
So the total stored charge at any given time, we know that that charge q is equal to the sum of the charge q 1 in the capacitor 1 and the charge q2 in the capacitor 2.
02:55
So we can say that this is the maximum charge this times 1 minus the s.
03:03
Exponential of minus the time divided by the constant, the time constant tau.
03:11
Or we can just have that the sum of these two charges...