00:01
So we have a circuit here where we're trying to find the current that's running across this 2 -home resistor, and we also want to find the potential difference between point a and point b.
00:12
So the way that we're going to do that is we're going to apply the loop rule and the junction rule in order to set up a system of equations where we can then solve for the unknown.
00:23
So we're going to do first is we're going to apply the loop or the junction rule to this point right here.
00:29
So we'll take notice of which current is coming in, so we can see i3 and i2 coming into the junction, and we have i1 coming out.
00:39
So we can write this as our first equation, as i1 is equal to i2 plus i3.
00:49
So now what we can do for a second equation is apply the loop rule.
00:54
And we're going to use this top loop first, and we're going to go counterclockwise, starting at the 12 -volt battery.
01:02
So our equation should look like this.
01:04
We'll have 12 minus 2 times i3.
01:08
And we have a minus here because we're going across the resistor in the direction of the current as it's drawn.
01:15
We'll then have minus 4 times i1 equal to 0.
01:22
And now doing the same going counterclockwise in this bottom loop here.
01:28
We'll have 8 minus 6 times i2 plus 2 times i3.
01:37
And we'll set that equal to zero...