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For the circuit shown in Figure P 18.20, calculate (a) the current in the $2.00-\Omega$ resistor and (b) the potential difference between points $a$ and $b, \Delta V=V_{b}-V_{a}.$

a. =\frac{28}{11}-\frac{18}{11}=\frac{10}{11}+m

b. \begin{array}{rl}{V_{k}=12 \mathrm{V}} & {V_{b}-v_{a}} \\ {V_{b}=12-2(I-i)=12-2\left(\frac{10}{11}\right) \cdot} & {=-2\left(\frac{10}{11}\right)} \\ {} & {=-1.82 \mathrm{V}} \\ {\text { ar }|\Delta V|=1.82 \mathrm{V} \text { and } b \text { is at lower potential }}\end{array}

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