We are given that the collector current $I_C = 2$ mA and the collector-emitter voltage $V_{CE} = 6$ V. We can use Ohm's law to find the value of $R_C$:
$$V_{CE} = I_C \times R_C$$
Rearranging for $R_C$:
$$R_C = \frac{V_{CE}}{I_C} = \frac{6 \,\text{V}}{2 \times
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