00:01
Hello, we're going to do a continuation of the previous problem that i answered on number 10.
00:06
So if you need to see how we went through that, please refer to that answer.
00:11
This problem asks for the equation of motion of the position of this mass and spring system shown in the red box on the left.
00:20
So we went through before and found the spring constant and we found the resonance frequency of this system to be 2 .23 hertz.
00:29
Now we want to know what is the equation as a function of time for this system.
00:36
And additionally, we know that the system starts with an additional displacement so that it's at 75 millimeters, and that we know it starts at a velocity of zero meters per second.
00:53
That was given in the problem.
00:55
The question is, what is the position equation as a function of time? if you refer to the text, we can start from the base definition, where x of t is going to be defined as x -not cosine omega -t plus x.
01:15
Dot not over omega -sign omega -t.
01:19
This is the definition of a harmonic oscillator like this problem and a spring in a mass that has some position, initial position, and initial velocity.
01:30
Now we need to get omega.
01:33
We do not have that, but we do know the resonance frequency, so we can easily get omega.
01:38
So recall that omega, the angular frequency, is equal to 2 pi times that resonance frequency.
01:51
So that's just a simple multiplication, 2 pi times 2 .23 hertz...