Question
For the equilibrium of a body on an inclined plane of inclination $45^{\circ}$, the coefficient of static friction will be :(a) greater than one(b) less than one(c) zero(d) less than zero
Step 1
We have a body on an inclined plane with an angle of inclination of $45^{\circ}$. The forces acting on the body are its weight $mg$ acting vertically downwards and the normal reaction $N$ acting perpendicular to the inclined plane. Show more…
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A body is in equilibrium on a rough inclined plane under its own weight. If the angle of inclination of the inclined plane is $\alpha$ and the angle of friction is $\lambda$, then: (a) $\alpha>\lambda$ (b) $\alpha>\lambda_{2}$ (c) $\alpha=\lambda$ (d) $\alpha>\lambda$
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