Question
For the following exercises, determine the slope of the tangent line, then find the equation of the tangent line at the given value of the parameter.$$x=2 t, \quad y=t^{3}, \quad t=-1$$
Step 1
The derivative of \(x = 2t\) is \(dx/dt = 2\), and the derivative of \(y = t^3\) is \(dy/dt = 3t^2\). Show more…
Show all steps
Your feedback will help us improve your experience
Amy Jiang and 81 other Calculus 2 / BC educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
For the following exercises, determine the slope of the tangent line, then find the equation of the tangent line at the given value of the parameter. $$ x=t+\frac{1}{t}, \quad y=t-\frac{1}{t}, \quad t=1 $$
Parametric Equations and Polar Coordinates
Calculus of Parametric Curves
For the following exercises, determine the slope of the tangent line, then find the equation of the tangent line at the given value of the parameter. $$x=2 t, \quad y=t^{3}, \quad t=-1$$
For the following exercises, find the equation of the tangent line to the given curve. Graph both the function and its tangent line. $x=\ln (t), \quad y=t^{2}-1, \quad t=1$
Conic Sections
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD