00:01
Okay, so we need to find the linear approximation for f of x is equal to sine squared of x at a equals zero, right? so remember the formula for the linear approximation, l of x, is equal to f of a plus f prime of a times x minus a.
00:26
So we need to fill in three things, f of a, f prime of a, and a.
00:32
All right.
00:33
So first, we can this fill in a.
00:37
That's just going to be zero, right? so next thing we need to fill in is f of a, which is just f of zero, f of zero, is equal to sine squared zero.
00:51
And remember if our unit circle, right? so zero is this angle here.
00:57
If we look at the y -axis, or y component of this point here, we get zero, right? so this is sine of zero or sine of zero squared or zero squared.
01:14
So that's just zero...