Question
For the following exercises, find the unit vector in the direction of the given vector $\mathbf{a}$ and express it using standard unit vectors. $$\mathbf{a}=\langle 4,-3,6\rangle$$
Step 1
The magnitude of a vector $\mathbf{a}=\langle a_1,a_2,a_3\rangle$ is given by $\sqrt{a_1^2+a_2^2+a_3^2}$. So, for $\mathbf{a}=\langle 4,-3,6\rangle$, the magnitude is $\sqrt{4^2+(-3)^2+6^2}=\sqrt{61}$. Show more…
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