Question
For the following exercises, solve the trigonometric equations on the interval $0 \leq \theta<2 \pi.$$$3 \sec \theta-2 \sqrt{3}=0$$
Step 1
We can do this by adding $2\sqrt{3}$ to both sides and then dividing by 3. This gives us: $$\sec \theta = \frac{2\sqrt{3}}{3}$$ Show more…
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