Question
For the following exercises, solve the trigonometric equations on the interval $0 \leq \theta<2 \pi.$$$4 \sin ^{2} \theta-2=0$$
Step 1
We can do this by dividing both sides of the equation by 4 and adding 2 to both sides to isolate $\sin^2 \theta$ on one side of the equation: $$4 \sin ^{2} \theta-2=0 \Rightarrow \sin ^{2} \theta=\frac{2}{4}=\frac{1}{2}$$ Show more…
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