00:01
In this problem, y varies jointly according to some variables.
00:06
So that means we have y is equal to some constant, as jointly as the square of x and z.
00:14
So that means we have x squared and z squared, and the square root of w and t.
00:24
And then we are given some information about what the variable is equal to.
00:29
So x is 2, z is 3, w16, t is 3, and y is 1.
00:37
And what this information would do is let us solve for our constant k.
00:43
So y is 1.
00:45
So we have a constant times x squared, 2 squared is 4.
00:51
Now z squared, we have 3 squared is 9.
00:58
The square root of 16 is 4.
01:01
And the square root of 3 is just root 3.
01:07
Now we see that we can simplify some things because we have 4 in the numerator and denominator.
01:13
And this tells us that k is equal to square root of 3 divided by 9.
01:28
And now if we want to solve the problem, we want to find what y is when x is 3, z is 2, w is 3...