00:01
All right, for this equation, we're going to try to figure out if we can set up an equation to show how quickly the bacteria grows.
00:08
And then we also want to know how quickly it takes to double.
00:13
So given what we know, which is not the initial value, we're going to use our data points that at five minutes, we have 360 bacteria, and at 20 minutes, we have 1 ,000.
00:22
We'll set up some equations to help us find the rate and the initial value.
00:25
To begin, 360 equals initial value a, ulor's constant of 5 times the rate.
00:35
We're going to solve for a here in dividing both sides, and we get a equals 360 e to the negative 5r.
00:48
We have negative 5 so that we can put our ular's constant with an exponent in the numerator.
00:54
Now hang on to this over here, and then go make our second essay.
01:00
Over here we have 1 ,000 equals are the value we just found for a, 625r times e2 .r.
01:14
Knowing our rules here, we can combine these terms, 1 ,000, plus 310e to the 15r, side both sides of 360, and we get approximately 2 .778, and they ask us for six significant digits.
01:34
We can go there.
01:38
Using a natural log on both sides, we can solve.
01:48
We know that the natural log of e is just one.
01:51
And the natural log of this value here is 1 .25.
01:59
And we'll divide both sides 16.
02:03
And our approximate value for r is 0 .068110...