00:01
So for this problem, we have that a pot of boiling soup with an internal temperature of 100 degrees fahrenheit was taken off the stove to cool in a 69 degree fahrenheit room.
00:17
After 15 minutes, the internal temperature of the soup was 95 degrees fahrenheit.
00:26
We are going to use newton's law of cooling to write a form.
00:30
Then models this situation.
00:33
So we're going to start off with newton's law of cooling, which is t of t, which stands for time.
00:42
I'm going to highlight t as for time.
00:45
And then a here is the difference between the initial temperature and the surrounding temperature times e to the k times t, and then k is the cooling rate of the continuous rate of cooling, sorry, plus t sub s and t sub s is the surrounding temperature.
01:11
So let's go ahead and start the problem.
01:17
So we're going to start with the fact that at our initial temperature, we have 100 degrees fahrenheit.
01:27
And so let's plug this in into our formula and see what we can do.
01:32
What we can solve for.
01:34
So we'll have 100 equals a.
01:39
We don't know what a is at this point.
01:42
E.
01:43
K times t, but t, notice t is zero.
01:50
Plus our surrounding temperature is 69.
01:54
So now we can go ahead and solve for a.
01:59
So let's see.
02:01
We are going to subtract 69 from both sides, so i'm just going to skip writing that step.
02:08
But let's go ahead in.
02:10
Subtract 69 from both sides, which means i'll have 31 equals a, e to the k times zero is zero.
02:21
Oh, and see, e to the zero gives us one.
02:25
So that means that a is going to be equal to 31...