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For the following two reactions, the first may occur but the second cannot. Explain.

$$\begin{aligned} \mathrm{K}^{0} & \rightarrow \pi^{+}+\pi^{-}(\text { can occur) }\\ \Lambda^{0} & \rightarrow \pi^{+}+\pi^{-} \text { (cannot occur) } \end{aligned}$$

Baryon number is not conserved for the 2nd reaction

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Rutgers, The State University of New Jersey

Numerade Educator

Hope College

University of Sheffield

first question, we're looking at these despotic election and wondering why try to figure out why this but a correction don't occur? And to do that, we're gonna start off by looking at the various conservation laws and see if the O bait in this particular election and if they're not, it is pretty likely the reason why the direction doesn't cook. But we start off 50 strongest conservation loss and go down the list off. Different conservation laws there are cited weaker right. Some of them are not very strong in debt. You it's sometimes a lot, so there's a probability of it. A Korean, but it's lower. All right then. But we need to start with the stronger conservation loss in which it's almost 100% that if it's not all beat, you will not occur. So the first law never gonna lawyer is the conservation off church. Now the left insect we have you touched off zero On the right hand side, we have plus 1 40 pi plus and minus 20. I minus So told her trashy zero. I smell so Cosby. Charge, charge charge is good. Thanks. We look at conservation off burial baron number There are a number for the left lung. Daisy Berry on particle. So this has a veritable plus one. My body pipe Last empire Mother has are reasons why am reasons Don't have any bare number. So they're zero and the total number of parents. Sorry. The total Berra number one right answer is zero and you can see that it is not conserved. So the bear numbers cannot conserved and probably is the reason why direction doesn't proceed.

National University of Singapore