00:02
Okay, so looking at this, to start, we need to simplify the numerator so we can factor out a negative 2.
00:11
So then i will be left with x squared minus 9.
00:16
And in the denominator, i also have x squared minus 9.
00:19
I'm going to continue factoring these, so i can break them down using difference of squares x plus 3, x minus 3.
00:27
In the denominator, i'll also have x plus 3, x minus 3.
00:32
And then they will actually all cancel.
00:35
So what this means is i have no vertical asymptote because i have nothing left in the denominator.
00:42
I do, however, have two holes.
00:45
I will have a hole where x is 3 and a hole where x is negative 3.
00:50
To find the y value of the hole, i will plug in negative 3 and 3 into the remaining x's, but since i'm only left with negative 2, there are in a remaining axis, so that means that that is my y value for both of those.
01:01
My horizontal asymptote, looking at my degrees, they are the same...