00:02
So we're given this function.
00:04
And the first thing is we need to find out what makes the denominator, what makes the denominator undefined? so we want to factor this.
00:15
So we have x plus 4, x minus 3 equals 0.
00:21
So the roots x equals 3 and x equals negative 4 are going to cause a problem.
00:26
That's going to make it undefined.
00:27
So my domain is going to be negative infinity to negative 4.
00:34
Negative 4 to positive 3, and then 3 to infinity.
00:39
That's my domain.
00:40
Now, the vertical asymptote is the denominator set equal to 0, and that's what we just did.
00:47
So we have two vertical asymptotes, x equals 3, and x equals negative 4.
00:52
One, two, three, four, one, two, three, four.
00:56
So i have one at x equals positive 3 and x equals negative 4.
01:09
Let's try to make this a little straighter.
01:14
Okay.
01:15
Now, are there holes in it? no, we can't cancel anything.
01:18
There's nothing to cancel when i have this over this.
01:22
So there are no removable discontinuities.
01:25
The horizontal asymptote is bottom heavy.
01:29
It's heavier on the bottom, so it's going to be approaching zero...