00:01
So here we know that the average power output of the source, p emit, would be equal to the delta e, the change in energy divided by delta t.
00:10
So this would be equal to 7 .2 nanojoules divided by two seconds.
00:16
So this is giving us 3 .6 nano, nanojoules per second, or we can say 3 .6 times 10 to the negative 9th joules per second or furthermore we can say 2 .25 times 10 to the 10th electron volts per second.
00:39
We can then say because the energy of each photon emitted, this is going to equal the plank's constant multiplied by the speed of light divided by the wavelength.
00:52
This would be equal to 1 ,240 electron volt nanometer divided by 600 nanometers.
01:03
This would be equal to 2 .07 electron volts.
01:10
And we can say that the rate, then this means that the rate at which photons are emitted by the source, are emit, would be equal to the power subemit, power emitted, divided by the energy of a single photon.
01:24
So this would be equal to 2 .25 times 10 to the 10th electron volts per second, and then this would be divided by 2 .07 electron volts...