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For the past 10 years, the unsaturated hydrocarbon 1,3-butadiene$({CH}_{2}={CH}-{CH}={CH}_{2})$has ranked 38th among the top 50 industrial chemicals. It is used primarily for the manufacture of synthetic rubber. An isomer exists also as cyclobutene:The isomerization of cyclobutene to butadiene is first-order and the rate constant has been measured as $2.0 \times 10^{-4} {s}^{-1}$ at $150^{\circ} {C}$ in a $0.53-{L}$ flask. Determine the partial pressure of cyclobutene and its concentration after 30.0 minutes if an isomerization reaction is carried out at 150 °C with an initial pressure of 55 torr.

38.35 $\mathrm{torr}$$1.0765 \times 10^{-3} \mathrm{mol} \mathrm{L}^{-1}$

Chemistry 102

Chapter 12

Kinetics

University of Central Florida

Brown University

University of Toronto

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Yeah. Live line. This is Ricky. And today we're going to determined the partial pressure of cycle up you teen and its concentration after 30 minutes of a diamond ization of a nice organization reaction. All right, so first, let us write down some of our knowns and unknowns, so we know that Psychlo U tane makes 13 You're dying. We know that this occurs is a first order reaction. You know that K is equal to two point in a long time since the negative forth per second. Um, you know that the volume of container that this was done that was done in was in a 0.5 liter flasks. Um, time, there's even a 30.2 minutes. Temperature is 150 degrees Celsius. Um, just in a change pool with 3 23 degrees Kelvin. Then we have a an initial pressure of 55. Poor. All right. A lot of variables. Okay. So first what? We're gonna do it? Iss right out our integrated rate law. So the highs, natural log of fee pressure, partial pressure, all right, cycle beauty mean is equal to negative, Katie, plus the natural log of the initial partial pressure of our reactant, huh? Okay. So we can substitute in some values in solve for Petey. So this equals negative K Times convert 30 minutes from the F K here, convert 30 minutes and seconds or 1800 seconds. Um, plus the natural log of 55 tour. And we get that P T is equal to 38 5 tour, which is the partial pressure of second Boutin. Who? All right, so first part of the problem has been solved, and now we want to get the concentration. So we're gonna be using Henry's law. So partial pressure is equal to are tee times. See? Gonna rearrange for C so C equals pee over. Our tea is equal to 38.35 Tour over 0.8 to 6. Which we're gonna be using. His are times for 23 help in my bed for 20 kelvin. And we find that e concentration of cycle beauty not the end of 30 minutes is 1.7 seven times 10 to the negative. Third molder of this video is helpful

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