00:02
Given p at negative square root 7, comma 8, square root of 3, and q at 5 square root 7, comma, negative square root of 3, we're going to determine the distance of these between these points, as well as the midpoint of that line segment.
00:19
So the distance of pq, we're going to use the distance formula, which says x2 minus x1 squared plus y2 minus y1 squared.
00:33
The first thing i'm going to do is label my points x1, x2, y2.
00:40
This helps me keep my thoughts organized and make sure i'm substituting correctly.
00:45
We get the distance of pq, and now we're going to substitute in x2 is 5 square to 7 minus x1, which is negative square to seven, so we get plus the square of seven.
01:03
Squared.
01:04
Plus y2 is negative square to three minus eight square to three squared.
01:13
The distance of pq equals the square root.
01:17
Five squared to seven plus square to seven is six square root of seven squared plus negative square to three minus eight squareths of three is nine square roots of three squared.
01:31
This gives me the distance of pq, 6 squared is 36, the square to 7 squared is 7, plus 9 square to 3 squared, so 9 squared is 81, square to 3 squared is 3...