00:01
We are continuing on with electrochemistry and the first thing we're looking to do is to determine the net ionic equation.
00:05
So what we need to do is exclude the spectator ions and this is what gives us our net ionic equation.
00:12
So what we have is 2n0 3 minus, add 3s0 as the gas, add 2h2o.
00:24
This is in equilibrium with 2no as a gas, a 3s0 4 2 .2 minus, add 4h plus.
00:39
So we can determine the electrode potential, e0, is equal to the e node of the reduction.
00:45
Positive 0 .964 volts.
00:48
And we add negative 0 .155 volts.
00:52
That's the e node of oxidation.
00:54
We get 0 .809 volts.
00:58
That's a positive value...