00:01
For this problem, we're going to be using hesse's law to determine the overall enthalpy of the reaction written in red.
00:08
And we're going to do that using those reactions written in black, for which we already have enfelps.
00:13
Let's start by looking at the reactants side.
00:17
You can see c2h4 is on the left, and it also appears on the left in the second reaction there.
00:24
So we're just going to rewrite that equation to start, and we're not going to flip it or multiply anything.
00:32
So the enthalpy is going to stay the same.
00:39
It's still going to be the negative 318 .7 kilojoules per mole.
00:46
And now this isn't the reaction we want, so we just have to manipulate the first reaction there to get it to cancel out.
00:54
So we have 4hcl, 02, and 2h2o.
01:02
And you can see that we need to cancel out 1⁄2 and 2hcl, and one water.
01:09
So what we're going to do with that equation is multiply by one -half...