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JF

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Problem 75

For the reaction $\mathrm{I}_{2}(g)+\mathrm{Cl}_{2}(g) \Longrightarrow 2 \mathrm{ICl}(g),$ calculate $K_{\mathrm{p}}$

at $25^{\circ} \mathrm{C}\left[\Delta G_{\mathrm{f}}^{\circ} \text { of } \mathrm{ICl}(g)=-6.075 \mathrm{kJ} / \mathrm{mol}\right]$

Answer

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## Discussion

## Video Transcript

Okay, So to start this question, we're gonna use our equation here. Felt g equals rt Ln KP So we will be solving for KP. So let's rearrange this equation. So we have itself for KP. So as you can see, I divided by a negative rt and then we're going to get rid of this natural log by using E. And we come out with this final equation. KP equals e raised the Delta G over rt. All right, so moving on, we're gonna look at our equation and I put our delta G values here, so we know rt, you know, are which is the constant It's eight 0.314 in temperature were given as to 98. So if we confined, Delta G will be able to find KP by plugging in values here in solving for KP. So, in order to solve four Delta G, we're going to use our products minus reactant since again you can find the Delta G values online if you just Google Delta G A formation. So here's our equation written out so we know exactly what we're looking for. And again always remember that if there is a coefficient. This also needs to go into the equation. So right here, we're going to have to times the delta g of I C L minus the Delta G of I two plus the Delta G of CO. Two. So from here, it's just a plug and drug. We're gonna plug the use numbers, and here Seal to is going to go over there, and this one will plug in right here. And don't forget to multiply this value by two. Since we have a cowfish and right here. All right, so if you want a positive view and do that calculation, it should come out to be negative 31 0.52 killer jewels. But we're gonna want to put this in jewels, since the units of our our value are in jewels. So we're gonna multiply that by 1000 which will give us negative. Do you 15 to 0. And that will be in jewels. Not right writing the units just because it takes me a while. I'm not very good of the pen. All right. So moving on since we have our delta G value right here, come off the negative sign. We have our delta G value right here. Let me make that a little more clear. We can plug that into our first equation. So I've written out the skeleton right here. So we're gonna plug or adult Aegean right here. 315 to 0. And then it's just plug and chug again. So we are going to come out with 3.35 times 10 to G fit.