00:02
So in this video we're going to talk about question 78 from chapter 20, which says for the rnfx compounds, the predicted in exercise 77, give the molecular structure, including bond angles.
00:14
So in exercise 77, we're told that radon reacts with fluorine to form fluorine compounds in the same way that xenon reacts with fluorine.
00:25
So we know that xenon forms fluorides that are xef2, xef4, and xef6.
00:31
So radon must form fluorides that are rnf2, r and f4, and rn f6.
00:38
So let's start drawing the lewis structures for these, and then we'll get the molecular structure.
00:44
So the first one is r &f2.
00:46
So we know that radon is going to bring eight valence electrons, and our two fluorine atoms will bring 14 valence electrons.
00:53
That gives us 22 electrons overall.
00:56
Then we can just draw radons with single bonds to both of the fluorine atoms.
01:01
And fill in the octet on the fluorine atoms, that leaves us six electrons left over.
01:08
So we put three lone pairs of electrons on radon.
01:12
So then we have two bonded atoms and three electron pairs.
01:16
That tells us that our molecule is linear.
01:19
So we have one fluorine atom above radon and one below radon and three electron pairs around the kind of equator of the molecule.
01:30
So the geometry is like that.
01:31
Linear and the bond angle is 180 degrees.
01:36
The next one we have is r and f4.
01:38
So we know that radon brings eight valiant electrons and each of our fluorines brings seven valence electrons.
01:43
That gives us 36 electrons overall.
01:46
So again, we just draw our central radon atom and then our fluorine atoms surrounding that with single bonds...