00:01
So now we'll work on problem 62 from chapter 6.
00:08
In this problem, we're given a table with quantum numbers, and it asks us to write which orbital goes with the quantum numbers.
00:17
And we're told not to worry about the x, y, and z subscripts.
00:21
And if the quantum numbers are right, not allowed, we should write not allowed.
00:26
So let's go ahead and put a little table here.
00:29
We have an n value, an l value, and x, ebb sub l value, and then we can write our orbital.
00:40
Let's go ahead and write in the example they give to practice.
00:48
So if we have an n value of two, an l value of one, and an m subl value of negative one, we know that n, the orbital should be, have a two at the beginning because n is equal to two.
01:07
And then the l value tells us.
01:08
That it's a p orbital and m sub al is negative one is a valid quantum number for l is equal to one so it's two p then we're given one zero zero n is equal to one so we put in a one uh l is equal to zero so it's an s orbital and zero is a valid quantum number for m sub l for l is equal to zero so it is 1s orbital.
01:42
Next, we're given 3, negative 3, and 2.
01:48
Now, the 3 here would suggest that we have a 3, the third energy level orbital.
01:57
However, we're given an l value of negative 3.
02:02
And when you have an l value of negative 3, it must be an f orbital.
02:06
However, the 3f orbital does not exist...