Question
For the vectors in Fig. $3-32,$ with $a=4, b=3,$ and $c=5,$ calcu-late $(a) \vec{a} \cdot \vec{b},($ b) $\vec{a} \cdot \vec{c}$ , and $(c) \vec{b} \cdot \vec{c} .$
Step 1
This means that the dot product of $\vec{a}$ and $\vec{b}$ is zero, because the dot product of two perpendicular vectors is always zero. So, we have: \[\vec{a} \cdot \vec{b} = 0\] Show more…
Show all steps
Your feedback will help us improve your experience
Derek Walkama and 85 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
For the vectors in Fig. 3 - 32 , with $a=4, b=3$, and $c=5$, calculate (a) $\vec{a} \cdot \vec{b}$, (b) $\vec{a} \cdot \vec{c}$, and $(\mathrm{c}) \vec{b} \cdot \vec{c} .$
For the vectors $\vec{A}, \vec{B},$ and $\vec{C}$ in $\mathrm{Fig} .1 .34,$ find the scalar products (a) $ \vec{A} \cdot \vec{B}$ (b) $\vec{B} \cdot \vec{C}$ (c) $\overrightarrow{\boldsymbol{A}} \cdot \overrightarrow{\boldsymbol{C}}$.
For the vectors given in Fig. 3-38, determine $(a) \overrightarrow{\mathbf{A}}-\overrightarrow{\mathbf{B}}+\overrightarrow{\mathbf{C}},(b) \overrightarrow{\mathbf{A}}+\overrightarrow{\mathbf{B}}-\overrightarrow{\mathbf{C}},$ and $(c) \overrightarrow{\mathbf{C}}-\overrightarrow{\mathbf{A}}-\overrightarrow{\mathbf{B}}$
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD