00:01
Hi, here in this given problem we have to focus only the two vectors, vector a and vector b.
00:06
That's why i am drawing only these two vectors over here.
00:12
First of all, this is x -axis, this is y -axis, vector b, a vector a that is along negative y -axis and this is vector b making an angle of 30 degree with a positive y -axis.
00:33
So, this is vector b whose length is 15 .0 meter and vector a having a magnitude 8 .00 meter.
00:50
This angle over here that is 30 .0 degree.
00:56
So, first of all, we have to find, we will find the components of vector b and vector a along x and y -axis.
01:08
So, here it will become by and here it will be bx.
01:14
Now ax that is 0 as vector a is purely along y -axis.
01:19
So, ay and this is along negative y -axis.
01:22
So, ay is equal to minus 8 .00 meter.
01:29
Bx that will be b sin 30 degree means 15 .0 into sin 30 that is half.
01:40
So, it comes out to be equal to 7 .5 meter and by that is b cos 30 degree means 15 .0 cos 30 degree.
01:54
So, it comes out to be equal to 13 .0 meter.
02:00
So, in the first part of the problem where we have to find vector a plus vector b.
02:06
So, first of all we find x component of this addition of a and b and that will be given by ax plus bx.
02:16
So, 0 plus 7 .5 means this is 7 .5 meter only and then we find its y component that will be ay plus by means this is minus 8 plus 13.
02:41
So, it comes out to be equal to plus 5 .0 meter.
02:46
So, magnitude of a plus b that will be given by using vector sum relation square of x component 7 .5 square plus y component 5 square and it is calculated to be equal to 9 .01 meter...