Question
For $w=\frac{1}{z}, u=\frac{x}{x^{2}+y^{2}}$ and $v=\frac{-y}{x^{2}+y^{2}} .$ If $y=x, u=\frac{1}{2} \frac{1}{x}, v=-\frac{1}{2} \frac{1}{x},$ and so $v=-u .$ The image is the line $v=-u$ (with the origin (0,0) excluded.)
Step 1
We want to find the image of the line $y = x$ under the transformation $w$. Show more…
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