00:01
We wish to find a number whose principal square root exceeds eight times the number by the largest amount.
00:08
So principal square root just means the positive square root of a number.
00:12
Okay, so what we're really looking for is we're looking to maximize the difference between square root of a number.
00:20
So let's call that x and eight times the number.
00:24
So that would be eight x.
00:26
Okay, so let's call this function f of x, which is the difference between the number.
00:31
The square root of x and eight times x.
00:33
So since we're trying to maximize this, that tells us we should go ahead and find its critical values, which means we need to find the derivative of f.
00:43
So let's go ahead and do that.
00:44
Derivative of f is equal to one half times x, the power of negative one half minus eight.
00:52
And we know that critical values happen where f prime of x is equal to zero or f prime of x doesn't exist.
01:00
Okay, so notice.
01:01
That when x is equal to zero, f prime of x doesn't exist.
01:07
But the square root of zero and a times zero is just zero.
01:12
So we'll keep that in the back of our head, but that's probably not going to be the largest difference.
01:20
So let's go ahead and find the other critical values, which is when we set f prime of x equal to zero.
01:26
So that's going to be, so let's rewrite this as one over two root x minus eight.
01:32
Okay, so let's go ahead and isolate 8.
01:35
We get 8 is equal to 1 over 2 square root x, or multiplying both sides by 2 gives us 16 is equal to 1 over square root x.
01:48
Okay, and then we're just going to flip both sides...