Since the line is tangent to the parabola at \(x = 2\), substitute \(x = 2\) into the equation of the parabola \(y = ax^2\) to find the \(y\)-coordinate of the point of tangency.
\[ y = a(2)^2 = 4a \]
Thus, the point of tangency is \((2, 4a)\).
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