71828. We want to find the values of n for which $(1 + 1/n)^n$ is within 1% and 0.0001% of e.
1% of e is approximately 0.02718, so we want to find n such that
$2.71828 - 0.02718 < (1 + 1/n)^n < 2.71828 + 0.02718$, or
$2.6911 < (1 + 1/n)^n < 2.74546$.
Similarly,
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