So, we have two cases to consider:
Case 1: $3x - 8 \ge 0$
In this case, we have $\sqrt{(3x - 8)^2} = 3x - 8$. Squaring both sides, we get $(3x - 8)^2 = (3x - 8)^2$. This equation is true for all $x$ in this case, so we need to find the values of $x$ that satisfy
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