Question
For which values of $b$ and $c$ does the system $x_1+x_2+b x_3=1, b x_1+3 x_2-x_3=-2$, $3 x_1+4 x_2+x_3=c$, have (a) no solution? (b) exactly one solution?(c) infinitely many solutions?
Step 1
The system given is: \[ x_1 + x_2 + b x_3 = 1 \] \[ b x_1 + 3 x_2 - x_3 = -2 \] \[ 3 x_1 + 4 x_2 + x_3 = c \] This can be represented as: \[ \begin{bmatrix} 1 & 1 & b \\ b & 3 & -1 \\ 3 & 4 & 1 \end{bmatrix} \begin{bmatrix} x_1 \\ x_2 \\ x_3 \end{bmatrix} = Show more…
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