00:01
Hello, so here we're giving the matrix 0 -a -b, negative a, 0, c, and then negative b, negative c, 0.
00:12
As for which constants here of a, b, and c, is this going to be invertible? well, we can try to convert this to the identity.
00:19
So we switch rows 2 and 1, and then we can multiply by negative 1 over a for the first row, and then times 1 over a, for the second row, and then we try to get to the identity.
00:32
But if we just perform operations, we end up with the matrix here, 1 -0 -negative c over a, and then 0 -1 -b -a.
00:44
But the last row becomes all zeros...