For $w=\operatorname{Ln} z, u=\log _{e}|z|$ and $v=\operatorname{Arg} z .$ The semi-circle $|z|=1, y>0$ may also be described by $r=1$ $0<\theta<\pi .$ Therefore $u=0$ and $0<v<\pi .$ The image is therefore the open line segment from $z=0$ to $z=\pi i.$