Question
Form the differential equation for the family of circles, touching the $x$ -axis at $(0,0)$. (Hint: $x^{2}+y^{2}-2 f y=0, f$ parameter)
Step 1
In this case, the circle touches the x-axis at $(0,0)$, so the center of the circle is $(0,r)$ and the radius is $r$. Therefore, the equation of the circle becomes $(x-0)^2 + (y-r)^2 = r^2$ which simplifies to $x^2 + (y-r)^2 = r^2$. Show more…
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